a rocket that has consumed all of its fuel continues to move upward slowed mostly by the force of gravity. If the rocket's mass is 75.0 g and it takes 1.2 sec for the rocket to stop, what is the change in the rocket's momentum?

what is the rockets stopping distance?

Assuming the value of g is 9.8m/s^2

Force*time=momentum
mass*g*time=momentum
be certain to change mass to kg.

velocity= momentum/mass
distance= velocity^time- g/2 *time^2

To determine the change in the rocket's momentum, we can use the equation:

Δp = m * Δv

Where:
Δp = Change in momentum
m = Mass of the rocket
Δv = Change in velocity

Since the rocket has stopped, the change in velocity (Δv) is equal to the final velocity (v) minus the initial velocity (u). In this case, the rocket's final velocity is 0 m/s, as it has come to a complete stop.

Using the equation of motion:
v = u + a * t

Where:
v = Final velocity (0 m/s)
u = Initial velocity (unknown)
a = Acceleration (due to the gravitational force of Earth, which is -9.8 m/s^2)
t = Time taken to stop (1.2 s)

Substituting the values into the equation, we can find the initial velocity (u):

0 = u + (-9.8 m/s^2) * 1.2 s

Solving for u:
u = 9.8 * 1.2 m/s
u = 11.76 m/s

Now that we have the initial velocity (u), we can calculate the change in momentum (Δp):

Δp = m * Δv
Δp = (0.075 kg) * (0 - 11.76 m/s)
Δp = -0.882 kg·m/s

The change in momentum of the rocket is -0.882 kg·m/s. The negative sign indicates that the momentum has been decreased in the opposite direction of the initial velocity.

Now let's calculate the rocket's stopping distance. Assuming the rocket is moving vertically upward, the stopping distance will be determined by the displacement traveled during the deceleration.

Using the kinematic equation:
s = ut + (1/2) * a * t^2

Where:
s = Stopping distance (unknown)
u = Initial velocity (11.76 m/s)
a = Acceleration (here, it is -9.8 m/s^2 as the rocket is decelerating due to gravity)
t = Time taken to stop (1.2 s)

Substituting the values into the equation:

s = (11.76 m/s) * 1.2 s + (1/2) * (-9.8 m/s^2) * (1.2 s)^2

Simplifying:

s = 14.11 m

Therefore, the rocket's stopping distance is approximately 14.11 meters.