calculate the force of a 300,00 kg jumbo jet that is accelerating 0.4m/square just before takeoff

To calculate the force exerted by the jumbo jet during takeoff, we can use Newton's second law of motion, which states that force is equal to mass multiplied by acceleration (F = m * a).

Given:
Mass of the jumbo jet (m) = 300,000 kg
Acceleration (a) = 0.4 m/s²

Now we can substitute these values into the equation to find the force:

F = m * a
F = 300,000 kg * 0.4 m/s²

Calculating the force:

F = 120,000 kg * m/s²

Therefore, the force exerted by the jumbo jet during takeoff is 120,000 Newtons.