how many totsl moles of ions are released when 0.83 mol of K3PO4 dissolves in water?

1 mole of K3PO4 contains 4 moles of ions: 3 moles K+ ions and 1 mole of PO4^-3 ions. Multiply the number of moles of the compound by 4 ions/mole.

To determine the total moles of ions released when 0.83 mol of K3PO4 dissolves in water, we need to consider the dissociation of the compound into its constituent ions.

The formula for potassium phosphate (K3PO4) suggests that it dissociates into three potassium ions (K+) and one phosphate ion (PO4^3-).

Hence, for every molecule of K3PO4 that dissolves, it releases three K+ ions and one PO4^3- ion.

Given that you have 0.83 mol of K3PO4, you can multiply this number by the number of moles of ions released per mole of K3PO4 to find the total moles of ions released.

Number of moles of ions released = (0.83 mol) x (3 + 1)

Number of moles of ions released = (0.83 mol) x (4)

Number of moles of ions released = 3.32 mol

Therefore, when 0.83 mol of K3PO4 dissolves in water, it releases a total of 3.32 moles of ions.

To determine the total moles of ions released when a substance dissolves in water, we need to consider the number of moles of each individual ion in the compound.

In K₃PO₄, there are three potassium ions (K⁺) and one phosphate ion (PO₄³⁻).

First, let's calculate the moles of each ion separately:

For potassium ions (K⁺):
Since there are three potassium ions in K₃PO₄, the number of moles of K⁺ ions is 3 times the moles of K₃PO₄.
Moles of K⁺ = 3 × 0.83 mol = 2.49 mol

For the phosphate ion (PO₄³⁻):
The number of moles of phosphate ions is the same as the number of moles of K₃PO₄.
Moles of PO₄³⁻ = 0.83 mol

Therefore, when 0.83 mol of K₃PO₄ dissolves in water, there are:
- 2.49 moles of K⁺ ions released, and
- 0.83 moles of PO₄³⁻ ions released.