multiply: (a-2)(2a-3)(a+7)
how do you do this problem?
multipy the first two (FOIL).
Then on the remaining two, muliply term by term.
Thanks
To multiply the expressions (a-2)(2a-3)(a+7), you can use the distributive property and perform the multiplication step by step.
Here's a breakdown of the process:
Step 1: Start by multiplying the first two expressions, (a-2) and (2a-3), using the distributive property.
(a-2)(2a-3) = a(2a-3) - 2(2a-3)
Step 2: Distribute the terms in each expression:
= 2a^2 - 3a - 4a + 6
Step 3: Simplify the expression:
= 2a^2 - 7a + 6
Now, you need to multiply this simplified result by the last expression, (a+7).
Step 4: Distribute the terms again:
(2a^2 - 7a + 6)(a+7) = 2a^2(a+7) - 7a(a+7) + 6(a+7)
Step 5: Multiply each term in the expression:
= 2a^3 + 14a^2 - 7a^2 - 49a + 6a + 42
Step 6: Simplify the expression by combining like terms:
= 2a^3 + 7a^2 - 43a + 42
Thus, the product of the expressions (a-2)(2a-3)(a+7) is 2a^3 + 7a^2 - 43a + 42.