12 wrestlers compete in a competition .if each wrestler wrestles one match each with each other wrestler ,what are the total numbers of matches.
NO!
choose 2 from 12 is
12!/(2!10!) or C(12,2) = 66
In how many ways can you choose 2 from 12 ?
To find the total number of matches in a competition where 12 wrestlers compete and each wrestler wrestles one match with each other wrestler, we can use the formula for combinations.
The formula to calculate the number of combinations is nC2, where n is the total number of participants.
For 12 wrestlers, the number of matches can be calculated as:
12C2 = (12 * 11) / (2 * 1) = 66.
So, there will be a total of 66 matches in this competition.
To determine the total number of matches in a competition where each wrestler wrestles one match with every other wrestler, we can use the concept of combinations.
In this scenario, we have 12 wrestlers, and each wrestler will wrestle one match with the other 11 wrestlers. To find the total number of matches, we need to calculate the number of combinations of 12 wrestlers taken 2 at a time.
The formula to calculate combinations is given by:
C(n, r) = n! / (r! * (n-r)!)
Where:
n = total number of items
r = number of items taken at a time
For our case, n = 12 wrestlers and r = 2 wrestlers taken at a time.
C(12, 2) = 12! / (2! * (12-2)!)
Calculating the factorial terms:
12! = 12 * 11 * 10 * 9 * 8 * 7 * 6 * 5 * 4 * 3 * 2 * 1
2! = 2 * 1
(12-2)! = 10 * 9 * 8 * 7 * 6 * 5 * 4 * 3 * 2 * 1
Simplifying the equation:
C(12, 2) = 12 * 11 / (2 * 1)
C(12, 2) = 132 / 2
C(12, 2) = 66
Therefore, the total number of matches in the competition is 66.