A chain consisting of 5 links, each of mass 0.100kg is lifted vertically with a constant acceleration of 2.50 m/s^2.
Calculate the force that link 2 exerts of link 1.
The force will be the total weight the link supports (Σmg) + the acceleration of 2.5 m/s² multiplied by the total mass (Σm) it supports.
F = Σm(g+a)
1.23
To calculate the force that link 2 exerts on link 1, you need to use Newton's Second Law, which states that the net force on an object is equal to its mass multiplied by its acceleration. Here's how you can use this law to solve the problem:
1. Determine the mass of link 1: Each link has a mass of 0.100 kg, and there are 5 links. So, the total mass of the chain is 5 * 0.100 kg = 0.500 kg. Since link 1 is at the bottom of the chain, it carries all the other links, so its mass is the total mass of the chain, which is 0.500 kg.
2. Calculate the force on link 1: The force on link 1 is equal to its mass multiplied by its acceleration. The acceleration is given as 2.50 m/s^2, so the force on link 1 is F1 = mass1 * acceleration = 0.500 kg * 2.50 m/s^2 = 1.25 N.
3. Determine the force exerted by link 2: Since link 2 is above link 1, it exerts an upward force on link 1 to lift it. According to Newton's Third Law of Motion, the force that link 2 exerts on link 1 is equal in magnitude and opposite in direction to the force that link 1 exerts on link 2. Therefore, the force exerted by link 2 on link 1 is also 1.25 N.
So, the force that link 2 exerts on link 1 is 1.25 Newtons.