A light bulb with resistance of _____________ Omega draws 900 mA from a 110 V household circuit.
To find the resistance of the light bulb, we can use Ohm's Law, which states that the resistance (R) is equal to the voltage (V) divided by the current (I). In this case, we are given the voltage (V = 110 V) and the current (I = 900 mA).
However, we need to convert the current to Amperes (A) from milliamperes (mA) as Ohm's Law requires using the same unit.
To convert milliamperes to Amperes, we divide the value by 1000. Therefore, 900 mA is equal to 0.9 A.
Now, we can use Ohm's Law to find the resistance.
R = V / I = 110 V / 0.9 A
Calculating this expression gives us the resistance:
R = 122.22 Ω
Hence, the resistance of the light bulb is approximately 122.22 Ω.