Two proteins are separated by capillary electrophoresis. The two proteins have the following physical characteristics:

Protein A: net charge = +6; MW = 64,500; partial specific volume = 0.700 cm3 / g
Protein B: net charge = +3; MW = 35,000; partial specific volume = 0.700 cm3 / g
The separation is carried out in a capillary that is 100 cm long, and 30,000 V is used for the separation. Which protein will reach the end of the capillary first, and how long will it take to migrate the length of the capillary? Assume that there is no electroosmotic flow. Show your work. (e = 1.6x10-19 C; viscosity of water = 0.0114g/cm-s; J = N-m = kg m2 /sec2; V = J/C)

to many questions no one will answer you lol..

hah, yea. I actually did get most of them answered elsewhere. just need one more!

To determine which protein will reach the end of the capillary first and calculate the time it takes to migrate the length of the capillary, we'll need to use the principles of electrophoresis and the formula for electrophoretic mobility.

Electrophoretic mobility (u) can be calculated using the formula:
u = (q / f) / (6πηr)

Where:
- u is the electrophoretic mobility
- q is the net charge of the protein
- f is the frictional coefficient of the protein
- η is the viscosity of the medium
- r is the radius of the protein, which can be calculated using the formula: r = sqrt((3V) / (4πN))

Where:
- V is the partial specific volume of the protein
- N is Avogadro's number (6.022 x 10^23 molecules/mol)

First, let's calculate the radius of each protein using the given data:
For Protein A:
V_a = 0.700 cm^3/g
MW_a = 64,500 g/mol
N = Avogadro's number = 6.022 x 10^23 molecules/mol

r_a = sqrt((3 * V_a) / (4πN))
= sqrt((3 * 0.700) / (4π * 6.022 x 10^23))
= 1.93 x 10^(-8) cm

For Protein B:
V_b = 0.700 cm^3/g
MW_b = 35,000 g/mol
N = Avogadro's number = 6.022 x 10^23 molecules/mol

r_b = sqrt((3 * V_b) / (4πN))
= sqrt((3 * 0.700) / (4π * 6.022 x 10^23))
= 1.37 x 10^(-8) cm

Next, let's calculate the electrophoretic mobility for each protein:
For Protein A:
q_a = +6 (net charge)
f_a = 6πηr_a (where η is the viscosity of water = 0.0114 g/cm-s)
u_a = (q_a / f_a)

For Protein B:
q_b = +3 (net charge)
f_b = 6πηr_b (where η is the viscosity of water = 0.0114 g/cm-s)
u_b = (q_b / f_b)

Finally, let's calculate the time for each protein to migrate the length of the capillary:
t = (100 cm) / u (time = distance / velocity)

For Protein A:
t_a = (100 cm) / u_a

For Protein B:
t_b = (100 cm) / u_b

By comparing the calculated electrophoretic mobility values (u_a and u_b), we can determine which protein will reach the end of the capillary first. The protein with the higher electrophoretic mobility will migrate faster.

To calculate the time taken for each protein to migrate the length of the capillary, we'll use the formula mentioned above.

Please substitute the values into the formulas to find the answers.