In a measurement of precipitation (rainfall), a raingauge with an orifice (collector) area of 30.50 in2 collects 1.30 litres of water over a period of 26 minutes and 45 seconds.[10]
Calculate:
1) The depth (amount) of rain that fell (in mm).
2) The intensity (mm h-1) at which the rain fell.
3) The volume (m3) of water that would have fallen on an area of 7.00 acres.
4)The discharge in m3 s-1 that would occur if all the water ran off the area in part c. in 3.00 hours.
5) If American gasoline is US$4.00 gallon-1, how much is that in CAN$ L-1?
conversions!
1 ha = 104 m2 (a hectare {ha} is an area 100 x 100m);
1 m = 3.2808 feet,
1 km2 = 106 m2 (103 x 103) m2;
1 inch = 25.4 mm;
1 m = 1000 (103) mm,
1” (inch) = 2.54 cm,
1 (Canadian) gallon = 4.55 L,
1 (American) gallon = 3.785L,
1 L = 1000 cm3,
1 mile = 5,280 feet,
1 mile2 = 640 acres
What did you get from your calculations?
hi, um the problem is that i didn't know how to start. i was just thinking.. V which is 1.3L/ the area would give me Depth but im in sure and i don't get conversions properly
The amount of rainfall that fell is equal to the depth of water collected in a rectangular water-tight box over the period of time.
A rain gauge is an instrument by which even minute amount of rainfall can be measureed accurately by using an oversized funnel and collecting the water in a container that can measure the quantity accurately. By dividing the amount of water collected divided by the area of the funnel (collecting area), we can obtain the amount of rainfall in mm or any other unit.
So the depth required is the quantities of water divided by the area, both in consistent units.
Let's work in centimetres.
1.3 litres = 1300 cm³
We know that 1 inch = 2.54 cm, so
1 in² = 2.54² cm²
30.50 in²
= 30.50*2.54^2 cm²
= 196.645 cm²
Amount of rainfall
= volume of water / area of collector area
= 1300 cm³ / 196.645 cm²
= 6.61 cm
= 66.1 mm
This measn that to do these questions, you will need to understand the definition of each term, make necessary converions of units to arrive at the correct answer.
Give a try for the remaining questions, start by
1. reading up and understanding the definitions of the terms, then
2. decide on the units you should be using,
3. do the conversions, then
4. do the calculations.
Start with Question 2 and post the steps that you have done if you have difficulties.
Umm why do you have to convert it to CM? So this is not right:
30.50 inches squared= 774.6999mm squared
1.3 litres= 1 300 000 mm cubed
Depth= 1 300 000/774.699
Depth = 1678.069147 mm
Im so confused with this stuff! Im in management so science is definitely not my area of expertise. Please help!
would you use the depth in part a) to calculate part b)?
I started with cm so that the numbers remain reasonable and can be "visualized" in size. You could have very well used mm all along, then there would be no conversion in the end.
For part 2, yes, exactly, you would first read up your teacher's notes to find out what is the definition of intensity. I believe it is the amount of rainfall (in mm) that fell in one hour, that is why the units are mm hr-1.
Then you use the amount calculated in part 1, in mm that fell in 26 minutes and 45 seconds, to calculate what would have fallen in 1 hour, if the intensity did not change. Can you proceed now with #2?
I understand now! Just to clarify my way of calculating depth isn't right? And also when I calculate part b), I have to convert 24 minutes and 45 secs into hours right? When I do that, do I convert it as 24.45 or 24mins separately 45 secs separately....sorry just confused!
Since there are 60 seconds in a minute, so
26 minutes 45 seconds is converted to
26+45/60 minutes, or 26.75 minutes.
In the same way, since there are 60 minutes in an hour, so 26.75 minutes converts to
26.75/60=0.44583 hour.
Now for the intensity of rainfall, which is measured by mm/hour, we divide the amount fallen in 26 minutes 45 seconds by the duration (in hours), so the intensity would be:
______ / 0.44583 = ______ mm/hour.
Thank you! I was wondering if the person who originally started this forum had any input ("pleasehelp").
Sorry, I assumed you're the original poster. Sometimes they change names along the way.
I hope you got something out of it!
Do you have a similar problem or was it by curiosity that you joined in?