[HELP WITH PART D PLEASE SCROLL DOWN] A 920 kg car is pulling a 300 kg trailer. Together, the car and trailer have an acceleration of 2.20 m/s2 in the forward direction. Neglecting frictional forces on the trailer, determine the following (including sign). the net force on the car
2024
(b) the net force on the trailer
660
(c) the force exerted by the trailer on the car
-660
(d) the resultant force exerted by the car on the road magnitude ____________ N
direction ________° measured from the left of vertically downwards
thanks!!!!!!!
a, you have to have on the car a pulling force equal to a*masscar+a*masstrailer
b. correct.
d. on the road, that is the same as the force (Horizontal) + weightcar (down)
so i should add the 2040 with what? whats the horozontal force?
wait what is the weight of the car 1010 kg?
The force pulling the car is exactly this
(masscar+masstrailer)acceleartion
To find the resultant force exerted by the car on the road, you can use Newton's second law of motion, which states that force is equal to mass multiplied by acceleration.
The net force acting on the car is the force that the car exerts on the road. Since the car is pulling the trailer, the force exerted by the car on the road is equal to the net force on the car.
Given that the mass of the car is 920 kg and the acceleration is 2.20 m/s², you can use the formula F = ma to calculate the net force on the car:
F(car) = m(car) * a(car)
= 920 kg * 2.20 m/s²
= 2024 N
Therefore, the magnitude of the resultant force exerted by the car on the road is 2024 N (newtons).
To determine the direction of the force, you need to consider the angle measured from the left of vertically downwards. Unfortunately, the given information does not specify this angle, so it is impossible to provide an answer without further details.