If a term paper consisted 42 pages,each containing 40 lines of 100 symbols each (counting each space as symbol)was to be encoded using unicode, how many bytes of storage space would be required?

Unicode is not a single coding system, there is UTF-8 which uses 1-4 byts for each character, and UTF-16 which uses 2-4 bytes for each character.

If you want to be conservative, you can count 4 bytes per character/symbol.
See
http://en.wikipedia.org/wiki/Unicode

336,000 bytes

To calculate the storage space required for encoding the term paper in Unicode, we need to consider the number of symbols and their encoding size.

Given:
- Number of pages: 42
- Lines per page: 40
- Symbols per line: 100
- Each space is counted as a symbol

First, let's calculate the total number of symbols:

Symbols per page = Lines per page * Symbols per line
Symbols per page = 40 * 100 = 4000 symbols

Total symbols in term paper = Symbols per page * Number of pages
Total symbols in term paper = 4000 * 42 = 168,000 symbols

In Unicode, each symbol is represented by 2 bytes. Therefore, to calculate the storage space required, we multiply the number of symbols by 2:

Storage space required = Total symbols in term paper * 2
Storage space required = 168,000 * 2 = 336,000 bytes

Hence, 336,000 bytes of storage space would be required to encode the term paper using Unicode.

To calculate the storage space required for the term paper, we need to consider the number of bytes each symbol would occupy when encoded using Unicode.

Unicode is a character encoding standard that provides a unique numeric value (code point) for each character across different writing systems and languages. In memory or storage, Unicode characters are typically represented using a sequence of bytes.

The size of a Unicode character representation can vary depending on the encoding scheme used. The most commonly used encoding scheme is UTF-8, which assigns a variable number of bytes to each character based on its code point.

In UTF-8, characters with code points from 0 to 127 (ASCII characters) are represented using a single byte. Characters with code points greater than 127 can take anywhere from 2 to 4 bytes, depending on their code point range.

To determine the storage space required for the term paper, we need to calculate the number of bytes used to represent each character and then multiply it by the total number of characters.

1. Calculate the number of characters per page:
Each page contains 40 lines, and each line contains 100 symbols. Therefore, there are 40 x 100 = 4000 symbols per page.

2. Calculate the total number of characters in the term paper:
The term paper consists of 42 pages, so there are 42 x 4000 = 168,000 symbols in total.

3. Calculate the storage space required:
Now, we need to estimate the average number of bytes per symbol. Since spaces are also counted as symbols, we can assume each symbol takes up an average of 1 byte. However, keep in mind that some characters may require more than 1 byte in UTF-8 encoding.

Therefore, the storage space required would be approximately 168,000 bytes.

Please note that this calculation assumes the use of UTF-8 encoding. If a different Unicode encoding scheme is used, the storage space calculation may vary.