how much tension must a rope withstand if it is used to accelerate a 1200-kg car vertically upward at .80 m/s^2?
Force required to accelerate the car vertically = m * (v^2)
= 1200 * (0.8^2)
= 1200 * 0.64
This force will be equal to the tension on the rope.
these are the answer choices though
Problem 10
13000 N
12000 N
11000 N
10000 N
13000N
12000N
11000N
10000N
tension=mg+ma=m(9.8+.8)= to two decimal places.
To determine the tension the rope must withstand, we need to calculate the force required to accelerate the car vertically upward. We can use Newton's second law of motion, which states that the force acting on an object is equal to its mass multiplied by its acceleration:
Force = Mass × Acceleration
Given:
Mass of the car (m) = 1200 kg
Acceleration (a) = 0.80 m/s²
Substituting the given values into the formula, we get:
Force = 1200 kg × 0.80 m/s²
Now let's calculate the force required to accelerate the car upward:
Force = 960 N
Therefore, the tension the rope must withstand is 960 Newtons.