A 2-hp motor drives a sanding belt. If the efficiency of the motor is 87% and that of the sanding belt 75% due to slippage, what is the overall efficiency of the system?
The answer has to be 65.25%. Can someone please help me to work it out?
The final efficiency is the product of the input efficiencies. What is .87*.75?
A 2-hp motor drives a sanding belt. If the efficiency of the motor is 87% and that of the sanding belt 75% due to slippage, what is the overall efficiency of the system?
given
n1=87%= 0.87
n2=75%=0.75
solution
nt=n1 x n2 x 100
nt=0.87 x 0.75 x 100
nt= 65.25%
To calculate the overall efficiency of the system, you need to multiply the individual efficiencies of the motor and the sanding belt together. Here's how you can work it out:
Step 1: Start with the efficiency of the motor. Given that the motor has an efficiency of 87%, you can express it as 0.87 (since percentages can be converted to decimal form by dividing by 100).
Step 2: Next, consider the efficiency of the sanding belt. It is stated that the efficiency of the sanding belt due to slippage is 75%. Similarly, convert this percentage into decimal form by dividing it by 100. Therefore, the efficiency of the belt is 0.75.
Step 3: Multiply the efficiency of the motor (0.87) by the efficiency of the sanding belt (0.75):
0.87 * 0.75 = 0.6525
Step 4: The result you obtain from the multiplication above, 0.6525, is the decimal form of the overall efficiency. To convert it back to a percentage, multiply by 100:
0.6525 * 100 = 65.25%
So, the overall efficiency of the system is 65.25%.