the perimeter of a rectangle is 202 inches. the length exceeds the width by 91 inches. find the length and width
width - x
length - x+91
Isn't 2x + 2(x+91) = 202 ?
i still cant figure it out
Just solve this simple equation.
2x + 2(x+91) = 202
Please let us know if you can't solve it -- and we'll go back to square one.
To find the length and width of a rectangle with a given perimeter and difference between length and width, you can set up a system of equations.
Let's say the width of the rectangle is "x" inches.
According to the given information, the length exceeds the width by 91 inches. So, the length can be expressed as "x + 91" inches.
The perimeter of a rectangle is calculated by adding twice the length and twice the width. Therefore, the equation for the perimeter is:
2(length) + 2(width) = 202
Substituting the values we have:
2(x + 91) + 2x = 202
Simplifying the equation:
2x + 182 + 2x = 202
4x + 182 = 202
4x = 202 - 182
4x = 20
Dividing both sides by 4:
x = 20 / 4
x = 5
So, the width of the rectangle is 5 inches.
Substituting this value back into the equation for the length:
Length = Width + 91
Length = 5 + 91
Length = 96
Therefore, the length of the rectangle is 96 inches, and the width is 5 inches.