find the indicated outputs for f(x)= 4x^2- 5x= f(0)=
f(-1)=
f(2)=
I don't see your problem.
I will be happy to check your figuring.
To find the indicated outputs for the given function f(x) = 4x^2 - 5x, we substitute the specific values of x into the function.
1. f(0):
To find f(0), we substitute x = 0 into the function:
f(0) = 4(0)^2 - 5(0)
Now, simplify:
f(0) = 0 - 0 = 0
Therefore, f(0) = 0.
2. f(-1):
To find f(-1), we substitute x = -1 into the function:
f(-1) = 4(-1)^2 - 5(-1)
Now, simplify:
f(-1) = 4(1) + 5 = 4 + 5 = 9
Therefore, f(-1) = 9.
3. f(2):
To find f(2), we substitute x = 2 into the function:
f(2) = 4(2)^2 - 5(2)
Now, simplify:
f(2) = 4(4) - 10 = 16 - 10 = 6
Therefore, f(2) = 6.
Hence, the indicated outputs for f(x) = 4x^2 - 5x are:
f(0) = 0,
f(-1) = 9,
f(2) = 6.