A squid with a mass of 15 kg ejects 1.8 kg of water downward through its funnel and moves from rest to a speed of 2.5 m/s (UP) from the sea bottom in 0.5s. Find the average force on the squid, neglecting drag forces and assuming constant acceleration.
force*time= changemomentum
force*time= 15*0 - 13.8*2.5
solve for force.
To find the average force on the squid, we can use Newton's second law of motion, which states that the force acting on an object is equal to its mass multiplied by its acceleration.
1. First, let's calculate the acceleration of the squid. We can use the equation for average acceleration:
a = (v - u) / t
Where:
a = acceleration
v = final velocity = 2.5 m/s (upward)
u = initial velocity = 0 m/s (since it was at rest)
t = time taken = 0.5 s
Plugging in the values, we get:
a = (2.5 m/s - 0 m/s) / 0.5 s
= 2.5 m/s / 0.5 s
= 5 m/s²
2. Next, we can calculate the net force acting on the squid using Newton's second law:
F = m * a
Where:
F = force (what we're trying to find)
m = mass of the squid = 15 kg (including the 1.8 kg of water)
a = acceleration = 5 m/s²
Plugging in the values, we get:
F = 15 kg * 5 m/s²
= 75 N
Therefore, the average force on the squid is 75 Newtons (N) upwards.