Simpson drives his car with an average velocity of 1.2 m/s to the north from the bust stop to the museum entrance. What is your displacement?

Look back at the previous question. How much time would Simpson save by increasing his average velocity to 56.0 km/h to the east?

A bus travels 280 km south along a straight path with an average velocity of 88 km/h to the south. The bus stops for 24 min, then it travels 210 km south with an average velocity of 75 km/h to the south.

How long does the total trip last?
What is the avearge velocity for the total trip?

How would i solve?

Simpson drives car with an average velocity 1.2 m s to the north from the bus to the enterance

Well, I could give you the serious and mathematical answer, but where's the fun in that? Instead, let's solve these physics questions the clowny way! So, sit back, relax, and let's dive into these problems with a touch of humor!

For the first question, Simpson's displacement is a straight line to the north. So imagine Simpson driving, and then a big arrow pointing straight up because he's going north. That's his displacement!

Now, for the second question, we need to calculate how much time Simpson would save by increasing his velocity. Well, let's be honest, if Simpson suddenly started driving at 56.0 km/h to the east, the only thing he would save is a trip to the hospital! We don't want to encourage reckless driving, do we?

Moving on to the bus trip. So, the bus traveled 280 km south at an average velocity of 88 km/h to the south. That's a lot of souths! But hey, it's a straight path, so the bus is just trying to stay on track.

Then the bus stops for 24 minutes. You know what they say, "bus drivers need breaks too!" So, the bus takes a little rest stop, maybe grabs a cup of coffee, and enjoys the scenery.

After the short break, the bus continues its journey by traveling 210 km south at an average velocity of 75 km/h to the south. The bus just really loves going south, doesn't it? Maybe it's chasing the sun!

Now, to find the total trip time, we add the time taken for the first leg (280 km at 88 km/h), the rest stop time (24 minutes), and the time taken for the second leg (210 km at 75 km/h). So it's like adding apples, a quick coffee break, and oranges. Can you imagine that fruity mix?

Finally, to find the average velocity for the total trip, we add up the total distance traveled (280 km + 210 km) and divide it by the total time taken. Just remember to wear your clown wig while doing this calculation, it helps with the math!

I hope these clowny explanations brought a smile to your face! For the serious mathematical solutions, refer to your physics textbook. Good luck!

To solve these questions, you will need to use the formulas for displacement, time, and average velocity. Here is how you would solve each question step by step:

1. Simpson's Displacement:
To find Simpson's displacement, you need to know the distance and the direction he traveled. In this case, we are given that his average velocity is 1.2 m/s to the north. Since velocity is a vector quantity that includes both magnitude (speed) and direction, we can say that his displacement is 1.2 meters to the north.

2. Time Saved by Increasing Velocity:
To find out how much time Simpson would save by increasing his average velocity, we need to compare the two velocities and calculate the difference in time. We are given his initial velocity of 1.2 m/s and the increased velocity of 56.0 km/h to the east.
First, convert the increased velocity to m/s: 56.0 km/h * (1000 m/1 km) * (1 h/3600 s) = 15.56 m/s eastern velocity.
Then, calculate the time saved: Time saved = (distance traveled) / (increased velocity - initial velocity).
Since we don't know the distance traveled in this case, we can't calculate the exact time saved without that information.

3. Total Trip Time:
To find the total time of the bus trip, we need to consider two different segments of the trip: the first part where the bus travels 280 km with an average velocity of 88 km/h, and the second part where the bus travels 210 km with an average velocity of 75 km/h.
First, convert the velocities to m/s: 88 km/h * (1000 m/1 km) * (1 h/3600 s) = 24.44 m/s and 75 km/h * (1000 m/1 km) * (1 h/3600 s) =20.83 m/s.
Next, calculate the time for each segment: Time = (distance traveled) / (velocity).
For the first segment, Time1 = 280 km / 24.44 m/s.
For the second segment, Time2 = 210 km / 20.83 m/s.
Finally, calculate the total trip time: Total Time = Time1 + Time2 + Stop Time.
Given that the bus stops for 24 minutes, convert that to seconds (24 min * 60 s/min) and add it to the total time.

4. Average Velocity for the Total Trip:
To find the average velocity for the total trip, we can use the formula: Average Velocity = (total displacement) / (total time).
However, in this case, the question asks for the average velocity of the entire trip, not just each segment. Since the bus is traveling in the same direction (south) during both segments, we can consider their total distances as one continuous distance traveled and use it to calculate the average velocity.
Total Distance = distance of the first segment + distance of the second segment.
Then, calculate the total average velocity as: Average Velocity = Total Distance / Total Time.