A car moving at a speed of 48.0 km/h accelerates 100.0 m up a steep hill, so that at the top of the hill its sped is 59.0 km/h. if the car's mass is 1100 kg, what is the magnitude of the net force acting on it?

i already know you have to change it to m/s but what do you do after that to find the magnitude of Force??

find a. vf^2=vi^2+2ad

solve that for a
Then, F=ma

499.498 N

i got 16.445 J

0.460 m/s 2

To find the magnitude of the net force acting on the car, you can use Newton's second law of motion, which states that force (F) equals mass (m) multiplied by acceleration (a).

First, convert the speeds from km/h to m/s. To do this, divide the given speeds by 3.6, since 1 km/h is equal to 1/3.6 m/s.

Initial speed (v1) = 48.0 km/h = 48.0 / 3.6 m/s = 13.33 m/s
Final speed (v2) = 59.0 km/h = 59.0 / 3.6 m/s = 16.39 m/s

Next, calculate the acceleration (a) using the equation:
a = (v2 - v1) / t

Since the distances are not given, we can use the fact that the car's speed is not constant over the whole distance, so we can use the average speed.

Average speed = (v1 + v2) / 2

Now we need to find the time (t) it took the car to accelerate from v1 to v2. We can use the formula for time (t) in terms of distance (d) and speed (v):
t = d / average speed

Given that the car accelerated 100.0 meters,

t = 100.0 m / [(13.33 m/s + 16.39 m/s) / 2]

Once you have calculated the value of 't', you can substitute the values back into the equation for acceleration (a):

a = (v2 - v1) / t

Finally, you can find the magnitude of the net force (F) acting on the car by using Newton's second law:

F = m * a

Substitute the given mass (m = 1100 kg) and calculated acceleration (a) into the equation to find the magnitude of the net force acting on the car.