Is the decomposition equation for copper sulphate hydrate (CuSO4.5H2O) as follows:
CuSO4+5H2O?
Thanks
CuSO4.5H2O ---> CuSO4+5H2O is correct if the heating is somewhat gentle. The solid product, anhydrous CuSO4 is white.
If you heat the hydrate too strongly, you will end up with black CuO.
The decomposition equation for copper sulfate pentahydrate (CuSO4·5H2O) can be written as:
CuSO4·5H2O → CuSO4 + 5H2O
In this reaction, the pentahydrate compound decomposes, yielding anhydrous copper sulfate (CuSO4) and evaporating water.
To determine the correct decomposition equation, it is important to consider the stoichiometric ratio of the components involved. In the case of copper sulfate pentahydrate, there are five water molecules associated with each molecule of copper sulfate.
To verify this decomposition equation, you can balance it by ensuring that the number of atoms is conserved on both sides of the reaction. Balancing the equation will help in confirming that the written decomposition equation properly represents the reaction.
Please note that when using chemical formulas, the dot symbol (·) indicates the presence of water molecules in the compound.