Two tuning forks are struck at the same time. One tuning fork has a frequency of 20 Hz while the second tuning fork has a frequency of 226 Hz. How many beats will result?

To find the number of beats resulting from two tuning forks with different frequencies, you need to calculate the difference between their frequencies. The number of beats is equal to the absolute value of this difference.

In this case, the tuning forks have frequencies of 20 Hz and 226 Hz. To find the number of beats, subtract the frequency of the first tuning fork from the frequency of the second tuning fork:

226 Hz - 20 Hz = 206 Hz

The absolute value of 206 Hz is 206 Hz. Therefore, the result is 206 beats.

Hence, when two tuning forks with frequencies of 20 Hz and 226 Hz are struck at the same time, 206 beats will be produced.

To calculate the number of beats that will result from two tuning forks with different frequencies, we need to find their beat frequency.

The beat frequency is the absolute value of the difference between the frequencies of the two tuning forks.

In this case, the frequency of the first tuning fork is 20 Hz, and the frequency of the second tuning fork is 226 Hz.

The beat frequency is calculated as follows:

Beat Frequency = |Frequency of Fork 1 - Frequency of Fork 2|

Substituting the given values:

Beat Frequency = |20 Hz - 226 Hz|

Simplifying,

Beat Frequency = |-206|

Taking the absolute value,

Beat Frequency = 206 Hz

Therefore, the number of beats that will result from striking these two tuning forks is 206 beats.