If the object travels a distance of 33.0 m in that time determine the following.
(a) The acceleration of the object during the 3 second period.
[ is the answer 33/9?] m/s2
(b) The maximum speed of the object during the 3 second period.
[is the answer 11?] m/s
(c) If the mass of the object is 1.50 kg, force 1 is 8 N and force 2 is 4 N, what is force 3 set to? [IS 2 THE ANSWER?]
1. 33 m in 3 sec means an average velocity of 11m/s
a) cannot be determined, as there is no starting nor finishing velocity stated.
b) ibid.
c)
Something is missing the problem.
To determine the answers to the questions:
(a) The acceleration of an object can be calculated using the formula:
acceleration (a) = change in velocity (v) / time (t)
In this case, the object travels a distance of 33.0 m in a time period of 3 seconds. Since velocity is the change in distance over time, we can calculate the velocity using the formula:
velocity (v) = distance (d) / time (t)
Substituting the given values, we have:
v = 33.0 m / 3 s = 11.0 m/s
Now we can calculate the acceleration using the formula above:
a = v / t = 11.0 m/s / 3 s ≈ 3.667 m/s^2
So, the correct answer for part (a) is approximately 3.667 m/s^2.
(b) The maximum speed of an object during a specific time period can be determined by finding the highest velocity the object reaches during that time. In this case, the velocity is already calculated in part (a) and is equal to 11.0 m/s. So, the correct answer for part (b) is indeed 11.0 m/s.
(c) To determine the value of force 3, we can use Newton's second law of motion, which states:
force (F) = mass (m) × acceleration (a)
Given that the mass of the object is 1.50 kg and force 1 is 8 N, force 2 is 4 N, we can calculate the acceleration:
a = (F1 + F2) / m = (8 N + 4 N) / 1.50 kg = 12 N / 1.50 kg = 8 m/s^2
Finally, to find force 3, we can rearrange the formula:
F3 = m × a = 1.50 kg × 8 m/s^2 = 12 N
So, the correct answer for part (c) is 12 N.