block of dry ice resting on a table is given a brief push. a moment later, which of the following forces act on the block?
friction.
gravity
When a block of dry ice is given a brief push, the following forces act on the block:
1. Applied force: The initial push given to the block is an applied force. This force is responsible for setting the block in motion.
2. Friction force: As the block moves across the table's surface, there is friction between the block and the table. This force opposes the motion of the block and acts in the opposite direction. The friction force depends on the nature of the surface and the weight of the block.
3. Normal force: The block of dry ice experiences a normal force from the table. The normal force is perpendicular to the table's surface and counteracts the force of gravity acting on the block. It prevents the block from falling through the table.
4. Weight force: The weight of the block, acting vertically downward, is another force that affects the block. It is the gravitational force acting on the block due to its mass.
These forces together determine the motion and behavior of the block of dry ice after it is given a brief push.
To determine which forces act on a block of dry ice resting on a table after it is given a brief push, we need to consider the physical principles involved.
When the block of dry ice is at rest on the table, it experiences the force of gravity acting downward. This force is known as the weight of the block, given by the equation W = m * g, where m is the mass of the block and g is the acceleration due to gravity.
When the block is given a brief push, it starts to move. As it moves, it experiences two forces: the force of friction and the force of air resistance.
1. Force of friction: When the block moves horizontally on the table, there is a force of friction acting in the opposite direction of its motion. This force arises due to the interaction between the dry ice and the table surface. The magnitude of the frictional force can be calculated using the equation F_friction = μ * N, where μ is the coefficient of friction and N is the normal force exerted by the table on the block. The normal force is equal to the weight of the block in this case.
2. Force of air resistance: As the block moves through the air, it also experiences a force of air resistance. This force opposes the block's motion and depends on its speed and shape. The magnitude of the air resistance force can be complex to calculate precisely, but generally, it increases as the speed of the block increases.
Therefore, after being given a brief push, the forces acting on the block of dry ice resting on the table are the force of gravity (weight), the force of friction, and the force of air resistance.