5.0 g of NaNO3 is dissolved in 50.0 g of water. The initial temperature of the water was 21 degrees Celsius and the final temperature of the water is 15.7 degrees Celsius.

1)Calculate the heat of solution, DeltaHsolution.
2) calculate the heat of solution, DeltaHsolution, per mole of NaNO3.

To calculate the heat of solution, DeltaHsolution, we can use the equation:

DeltaHsolution = q / n

Where:
- DeltaHsolution is the heat of solution
- q is the amount of heat exchanged in the process
- n is the number of moles of solute

Let's start with the first question:

1) Calculate the heat of solution, DeltaHsolution.

To calculate the amount of heat exchanged (q), we can use the equation:

q = m * C * DeltaT

Where:
- q is the amount of heat exchanged
- m is the mass of the water
- C is the specific heat capacity of the water
- DeltaT is the change in temperature

For water, the specific heat capacity (C) is approximately 4.18 J/g°C.

Substituting the given values:
- m = 50.0 g
- C = 4.18 J/g°C
- DeltaT = final temperature - initial temperature = 15.7°C - 21°C = -5.3°C

q = 50.0 g * 4.18 J/g°C * (-5.3°C) = -1103.7 J

Note: The negative sign indicates that heat is released, not absorbed.

Next, we need to calculate the number of moles of NaNO3:

The molar mass of NaNO3 is:
Na (22.99 g/mol) + N (14.01 g/mol) + 3O (3 * 16.00 g/mol) = 85 g/mol

Given:
- Mass of NaNO3 = 5.0 g

Number of moles of NaNO3 = 5.0 g / 85 g/mol = 0.0588 mol (rounded to four decimal places)

Now we can calculate DeltaHsolution:

DeltaHsolution = q / n = -1103.7 J / 0.0588 mol = -18787.2 J/mol (rounded to one decimal place)

Therefore, the heat of solution, DeltaHsolution, is approximately -18787.2 J/mol.

2) Calculate the heat of solution, DeltaHsolution, per mole of NaNO3.

Since we already have the heat of solution, DeltaHsolution, in J/mol, we can directly use that value. So the heat of solution, DeltaHsolution, per mole of NaNO3 is also approximately -18787.2 J/mol.