Suppose a basketball player is an excellent free throw shooter and makes 91% of his free throws (i.e., he has a 91% chance of making a single free throw). Assume that free throw shots are independent of one another. Suppose this player shoots five free throws. Find the probability that he makes all five throws.
hey im NOT sure, but i think it's 45.5% because 5 x 0.91 = 45.5
The probability that he makes five out of his five shots
= (.91)(.91)(.91)(.91)(.91)
= (.91)^5
= .624 or 62.4%
To find the probability that the basketball player makes all five free throws, we need to multiply the probabilities of making each individual free throw since they are independent.
The probability of making a single free throw is 91%, which is equivalent to 0.91.
Therefore, the probability of making all five throws is:
0.91 * 0.91 * 0.91 * 0.91 * 0.91 = 0.91^5 ≈ 0.624 = 62.4%
So, the probability that the player makes all five free throws is approximately 62.4%.
To find the probability that the basketball player makes all five free throws, we need to multiply the probability of making a single free throw by itself five times. Since each free throw is independent, the probability remains the same for each throw.
Given that the player has a 91% chance of making a free throw, the probability of making a single free throw is 0.91 (91% written as a decimal).
To find the probability of making all five throws, we calculate:
0.91 * 0.91 * 0.91 * 0.91 * 0.91 = 0.6240321
So, the probability that the basketball player makes all five free throws is approximately 0.624, or 62.4%.