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Suppose a basketball player is an excellent free throw shooter and makes 91% of his free throws (i.e., he has a 91% chance of making a single free throw). Assume that free throw shots are independent of one another. Suppose this player shoots five free throws. Find the probability that he makes all five throws.

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  1. hey im NOT sure, but i think it's 45.5% because 5 x 0.91 = 45.5

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  2. The probability that he makes five out of his five shots
    = (.91)(.91)(.91)(.91)(.91)
    = (.91)^5
    = .624 or 62.4%

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