write an equation of the line containing the given pointand parrallto the given line. express the answer in the form y=mx+b
(-2,4); 9x=5y+3
As Jim explained to you in such detail
for an almost identical question,
since the lines are parallel, all that will change is the constant.
So your new equation will look like
9x = 5y + c, where is c is the number that will change.
but (-2,4) lies on this line, so
9(-2) = 5(4) + c
-18 = 20 + c
-38 = c
now our new equation is 9x = 5y - 38
but you wanted it in the form y = mx + b
9x + 38 = 5y
5y = 9x + 38
y = (9/5)x + 38/5