last year lein earned $1,700 more than her husband. toegther they earned $50,200. how much did each of them earn?
Let x = the amount the husband earned.
x + x + 1700 = 50,200
2x = 50,200 - 1700
2x = 48500
x = ?
do i add
Can you solve the equation? What number does x equal?
= 48502
Oh, my! You don't understand even the most elementary algebra, do you?
What grade are you in?
2x = 48,500 means that 2 times some number is 48,500.
To solve this problem, divide both sides of the equation by 2.
x = 48,500 divided by 2 = 24,250
Therefore, her husband earns $24,250.
Lein earns $1,700 more than her husband. She earns $24,250 + 1,700 = $25,950.
To determine how much each of them earned, you can use a system of equations. Let's assume Lein's earnings are represented by L and her husband's earnings are represented by H.
From the problem, we have two pieces of information:
1. Lein earned $1,700 more than her husband: L = H + $1,700.
2. Together they earned $50,200: L + H = $50,200.
Now we can solve the system of equations to find the values of L and H.
Substituting the value of L from equation 1 into equation 2, we get:
(H + $1,700) + H = $50,200
2H + $1,700 = $50,200
Next, subtract $1,700 from both sides:
2H = $50,200 - $1,700
2H = $48,500
Divide both sides by 2:
H = $48,500 / 2
H = $24,250
Now that we have found H, we can substitute it back into equation 1 to find L:
L = $24,250 + $1,700
L = $25,950
Therefore, Lein earned $25,950 and her husband earned $24,250 last year.