f(x)= -7(cos(s^3))(tan(s^2)), find f'(x).
I got 21s^2cos(s^3) x 2s(sec^2(s^2)) but it is wrong...
To find f'(x) of a product, we would subdivide the expression into two pices, such as:
From
f(x) = -7 cos(s³) tan(s²)
we put
u=cos(s³)
v=tan(s²)
then
f(x)=-7uv
f'(x)=-7(u du/dx + v dv/dx)
where
du/dx = d(cos(s³))dx
= -sin(s³) d(s³)/dx [note use of the chain rule]
= -3s²sin(s³)
...
Can you take it from here?