Write each expression as a products of its factors.
56ab
Thank you
56= 28*2
= 2*2*7*2
so
56ab= 2^3 * 7*a*b
To write the expression 56ab as a product of its factors, we need to decompose the number 56 into its prime factors.
Step 1: Prime factorize 56:
To find the prime factors of 56, we start by dividing it by the smallest prime number, which is 2:
56 ÷ 2 = 28
Since 28 is also divisible by 2, we continue dividing:
28 ÷ 2 = 14
Dividing 14 by 2 again, we have:
14 ÷ 2 = 7
Now we can't divide 7 any further, so 7 is a prime number.
Therefore, the prime factorization of 56 is 2 × 2 × 2 × 7, or 2^3 × 7.
Step 2: Write the expression as a product of its factors:
Now that we have the prime factorization of 56, we can rewrite the expression 56ab as a product of its factors:
56ab = (2 × 2 × 2 × 7) × a × b
We can rearrange the factors:
56ab = (2 × a × 2 × b × 2 × 7)
Simplifying further, we get:
56ab = 2^3 × a × 2 × b × 7
And finally, combining like terms, we have:
56ab = 8ab × 7
Therefore, the expression 56ab can be written as the product of its factors as 56ab = 56ab × 1.