A 4430-kg helicopter accelerates upward at 2.2 m/s2. What lift force is exerted by the air on the propellers?
The propellers have to overcome the weight of the helicopter in addition to lifting it.
Force = ma = mass * (g + 2.2) m/s²
Can you take it from here?
Yes! Thank you so much! I realized that you had to put gravity in but I couldn't figure out where. Thanks again!
You're very welcome!
To find the lift force exerted by the air on the helicopter's propellers, you can use Newton's second law of motion, which states that the force exerted on an object is equal to its mass multiplied by its acceleration.
In this case, the force we're looking for is the lift force, which counteracts the force of gravity and keeps the helicopter airborne. The acceleration we're given is the upward acceleration of the helicopter, and the mass of the helicopter is 4430 kg.
Using the formula F = ma, where F is the force, m is the mass, and a is the acceleration, we can plug in the values:
Force (lift force) = mass × acceleration
Force = 4430 kg × 2.2 m/s^2
Calculating this, we get:
Force = 9732 N
Therefore, the lift force exerted by the air on the helicopter's propellers is 9732 N.