Can someone please check to see if I balanced this chem. equation which is an incomplete combustion reaction:

2C3H8 + 11O2 ->> 3CO2 + 4H2O +2CO +C(s)

My answer:
7C3H8 +22O2 -->> 6CO2 + 28H2O +4CO +11C

Thanks!

If the purpose is to balance the equation, it is balanced.

Thank you.

To check if your chemical equation is balanced, you'll need to count the number of atoms on both sides of the equation. Here's how you can do it:

First, let's count the number of atoms of each element on the reactant side (left side) of the equation:

- Carbon (C): 2 × 3 = 6
- Hydrogen (H): 2 × 8 = 16
- Oxygen (O): 11 × 2 = 22

Now, let's count the number of atoms on the product side (right side) of the equation:

- Carbon (C): 3 + 2 + 1 = 6
- Hydrogen (H): 4 × 2 + 28 = 36
- Oxygen (O): 2 × 3 + 4 + 11 = 21

Comparing the counts, we can see that the number of carbon and oxygen atoms is balanced. However, the number of hydrogen atoms is not equal on both sides.

To balance the equation, you'll need to adjust the coefficients. In this case, you can add a coefficient of 7 in front of C3H8 on the reactant side to balance the hydrogen atoms. By doing so, the equation becomes:

7C3H8 + 22O2 -> 21CO2 + 28H2O + 2CO + 11C

Now, let's recheck the atom counts:

- Carbon (C): 7 × 3 = 21
- Hydrogen (H): 7 × 8 = 56
- Oxygen (O): 22 × 2 = 44

On the product side:

- Carbon (C): 21 + 2 + 11 = 34
- Hydrogen (H): 28 × 2 = 56
- Oxygen (O): 21 × 2 = 42 + 2 + 11 = 55

Now, we can see that the equation is balanced in terms of carbon, hydrogen, and oxygen atoms.

Therefore, the balanced equation is:

7C3H8 + 22O2 -> 21CO2 + 28H2O + 2CO + 11C

I hope this helps! Let me know if you have any further questions.