Calculate q in J when 2.02 g of ice is cooled from -22.6°C to -73.8°C (cice = 2.087 J/g·K). Do not add units to your answer.
To calculate the heat (q) in joules, we need to use the formula:
q = m * c * ΔT
Where:
m = mass of the substance (in grams)
c = specific heat capacity of the substance (in J/g·K)
ΔT = change in temperature (in °C or K)
Given:
m = 2.02 g
cice = 2.087 J/g·K
ΔT = (-73.8°C) - (-22.6°C) = -51.2°C
Now we can plug in the values and calculate q:
q = 2.02 g * 2.087 J/g·K * -51.2°C
Let's first convert the change in temperature from Celsius to Kelvin:
ΔT = -51.2°C + 273.15 K = 221.95 K
q = 2.02 g * 2.087 J/g·K * 221.95 K
Multiplying these values, we get:
q ≈ 933.87 J
Therefore, q is approximately 933.87 J.
To calculate the heat energy (q) in joules (J), we can use the equation:
q = m * c * ΔT
where:
m is the mass of the substance (in grams),
c is the specific heat capacity of the substance (in J/g·K),
ΔT is the change in temperature (in degrees Celsius or Kelvin).
Given:
m = 2.02 g (mass of ice)
c = 2.087 J/g·K (specific heat capacity of ice)
ΔT = -73.8°C - (-22.6°C) = -51.2°C
Since the specific heat capacity is given in J/g·K, make sure that the mass is in grams and the temperature difference is in °C or K.
Substitute the given values into the equation:
q = 2.02 g * 2.087 J/g·K * -51.2°C
Now, calculate q:
q = -217.63264 J
Hence, the heat energy (q) when 2.02 g of ice is cooled from -22.6°C to -73.8°C is -217.63264 J.