A 27.4 g sample of metal X requires
131 calories of energy to heat it from 10.0◦C to 90.0◦C. Calculate the specific heat of metal X.
Answer in units of J/g ·◦ C.
Any help would be greatly appreciated
change 131 c to Joules.
divide by 27.4
divide by 80
Sorry, but I don't understand. Haven't done this in a while. I divided 137 J by 27.4 and then 80, but I get 0.05 as my answer.
is that correct?
You didn't change 131 calories to Joules first.
Oh, haha.. Thanks a lot. Very helpful. =]
To calculate the specific heat of metal X, you need to use the formula:
q = mcΔT
Where:
q is the energy transferred in calories (131 calories in this case).
m is the mass of the metal X in grams (27.4 g in this case).
c is the specific heat capacity of the metal X in J/g ·◦C (what we're trying to find).
ΔT is the change in temperature in ◦C (90.0◦C - 10.0◦C = 80.0◦C in this case).
First, let's convert the energy from calories to joules. There are 4.184 J in 1 calorie, so:
q = 131 calories * 4.184 J/calorie = 547.904 J
Now we can rearrange the formula to solve for c:
c = q / (m * ΔT)
Substituting the values:
c = 547.904 J / (27.4 g * 80.0◦C)
Now we just need to perform the calculation:
c ≈ 0.800 J/g ·◦C
Therefore, the specific heat of metal X is approximately 0.800 J/g ·◦C.