If the standard deviation of the distribution of the difference between means is .76, what is the t score?
- (15 - 23) / 0.76 = -10.53
- (0.76)(15-23) = -8.00
- [(6.5 + 4.5)/2][0.76] = 4.18
- (55 - 51) / 0.76 = 5.26
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To determine the t score, we need to know the formula for calculating it. The formula for the t score is:
t = (x1 - x2) / s
Where:
- x1 is the difference between the means
- x2 is the hypothesized difference between the means (which is usually 0)
- s is the standard deviation of the distribution of the difference between means
In this case, x1 = -8.00 (from the second option you provided) and s = 0.76 (given in the question). Since we don't have information about x2 (the hypothesized difference), let's assume it's 0 (as is commonly done).
Plugging the values into the formula, we get:
t = (-8.00 - 0) / 0.76 = -10.53
Therefore, the t score in this case is -10.53.