This is a confusing problem to me also, can someone please help me?
What are the odds in favor of getting at least one head in three successive flips of a coin?
Pr(three heads)= 1/2*1/2*1/2
Pr(one head in three flips)= Pr(HTT)+Pr(HHT) + Pr(HHH)+ Pr(THT)+Pr(TTH)+ Pr(THH)+Pr(HTH)
= oddly enough 1/2*1/2*1/2 * 7
check me to make certain I included all the ways to get at least one head.
think on that one.
7/8
One comment. On the at least on head in three flips should equal the 1-Pr(no heads)0r 1=Pr(TTT) or 1-1/2*1/2*1/2= 7/8
post that same question in the little jiskha box search, and you'll find what you need.
Thanks alot!!!
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Certainly, I can help you with that! To find the odds in favor of getting at least one head in three successive flips of a coin, we need to calculate the probability of getting at least one head in three flips.
First, let's consider the probability of not getting a head in a single flip. Since a fair coin has two equally likely outcomes (heads or tails), the probability of getting tails in one flip is 1/2. Thus, the probability of not getting a head in one flip is also 1/2.
To find the probability of not getting a head in three successive flips, we can multiply the probabilities of not getting a head in each flip since the events are independent. So, the probability of not getting a head in the first flip is 1/2, in the second flip is also 1/2, and in the third flip is again 1/2. Multiplying these probabilities together, we get:
(1/2) * (1/2) * (1/2) = 1/8
Now, to find the probability of getting at least one head, we can subtract the probability of not getting a head from 1 (since the sum of all possible outcomes must equal 1). So, the probability of getting at least one head in three flips is:
1 - 1/8 = 7/8
Now, to convert this probability into odds, we can calculate the odds in favor using the formula: odds in favor = probability of the event happening / probability of the event not happening.
In this case, the probability of the event happening is 7/8, and the probability of the event not happening is 1/8. Therefore, the odds in favor of getting at least one head in three flips are:
(7/8) / (1/8) = 7/1
So, the odds in favor are 7 to 1.