What is the mass of La2(C2O4)3*9H2O, can be obtained from 650mL of 0.0170 M aq solution of LaCl3 by adding a stoichiometric amount of sodium oxalate.

I don't know how to balance the equation for this..i started:

LaCl3+ Na2C2O4 -> La2(C2O4)3*9H2O + NaCl

You need to show the 9H2O on the LHS, from then on balancing it should be straight forwward. Balance the La atoms on the LHS then balance the Cl atoms on the RHS. Then balance the Na atoms on the LHS and you should find the oxalates will then already balance.

To balance the equation for the reaction between LaCl3 and Na2C2O4, you need to make sure that the same number of each type of atom exists on both sides of the equation.

Here's how you can balance the equation step by step:

1. Start by writing the formula for each compound involved in the reaction:
LaCl3 + Na2C2O4 -> La2(C2O4)3*9H2O + NaCl

2. Count the number of each type of atom on one side of the equation and compare it to the other side. Begin by balancing the atoms that appear in the fewest compounds first. In this case, we will start with the chlorides (Cl).

3. There are three chloride atoms on the left side (from LaCl3) and only one on the right side (from NaCl). To balance the chlorides, add a coefficient of 3 in front of NaCl:
LaCl3 + Na2C2O4 -> La2(C2O4)3*9H2O + 3NaCl

4. Now, let's balance carbon atoms. There are two carbon atoms in Na2C2O4 and 12 carbon atoms in La2(C2O4)3*9H2O. Therefore, you'll need to multiply the coefficient in front of Na2C2O4 by six:
LaCl3 + 6Na2C2O4 -> La2(C2O4)3*9H2O + 3NaCl

5. Next, let's balance oxygen atoms. There are eight oxygen atoms in Na2C2O4 and 36 oxygen atoms in La2(C2O4)3*9H2O. To balance the oxygens, multiply the coefficient in front of Na2C2O4 by four:
LaCl3 + 24Na2C2O4 -> La2(C2O4)3*9H2O + 3NaCl

6. Finally, let's balance the lanthanum (La) atoms. There is one lanthanum atom in LaCl3 and two lanthanum atoms in La2(C2O4)3*9H2O. To balance the lanthanum atoms, multiply the coefficient in front of LaCl3 by two:
2LaCl3 + 24Na2C2O4 -> La2(C2O4)3*9H2O + 3NaCl

Now the equation is balanced, and the stoichiometric ratio between LaCl3 and La2(C2O4)3*9H2O is 2:1.