What is the percent yield of CO2 if the reaction of 10.0g of CO with excess O2 produces 12.8g of CO2?

81.50%

pooopy

To calculate the percent yield of CO2, you need to compare the actual yield (which is the amount of CO2 obtained from the reaction) to the theoretical yield (which is the amount of CO2 that should be obtained according to stoichiometry).

Let's start by writing and balancing the chemical equation for the reaction:

2CO + O2 → 2CO2

From the balanced equation, you can see that 2 moles of CO react to produce 2 moles of CO2.

To find the theoretical yield of CO2, we need to consider the molar mass of CO2.

The molar mass of CO2 is calculated by adding up the molar masses of carbon (C) and oxygen (O) atoms:

C: 12.01 g/mol
O: 16.00 g/mol (x2 for two oxygen atoms)

Molar mass of CO2 = 12.01 g/mol + (16.00 g/mol x 2) = 44.01 g/mol

Now, let's calculate the theoretical yield of CO2:

The number of moles of CO2 can be found by dividing the mass of CO2 by the molar mass of CO2:

moles of CO2 = mass of CO2 / molar mass of CO2
moles of CO2 = 12.8 g / 44.01 g/mol ≈ 0.2909 mol

Since the balanced equation shows a 1:1 ratio between CO and CO2, we can conclude that the number of moles of CO used in the reaction is also 0.2909 mol.

Now, let's calculate the theoretical yield of CO using the molar mass of CO:

The molar mass of CO is calculated by adding the molar masses of carbon (C) and oxygen (O):

C: 12.01 g/mol
O: 16.00 g/mol

Molar mass of CO = 12.01 g/mol + 16.00 g/mol = 28.01 g/mol

The mass of CO can be found by multiplying the number of moles of CO by the molar mass:

mass of CO = moles of CO x molar mass of CO
mass of CO = 0.2909 mol x 28.01 g/mol ≈ 8.135 g

Now that we have the measured mass of CO2 (12.8 g) and the theoretical mass of CO2 (44.01 g/mol x 0.2909 mol = 12.8149 g), we can calculate the percent yield.

Percent yield = (actual yield / theoretical yield) x 100
Percent yield = (12.8 g / 12.8149 g) x 100 ≈ 99.9%

Therefore, the percent yield of CO2 in this reaction is approximately 99.9%.

2CO + O2 ==> 2CO2

Convert 10.0 g CO to moles. moles = grams/molar mass
Convert moles CO to moles CO2 using the coefficients in the balanced equation. That is a 1:1 ratio.
Convert moles CO2 to grams. Grams = moles x molar mass.