This is another problem that I need clarification on since no one seems to be of any help at my school,

A pulley system is used to lift a 52- crate.Note that one chain connects the upper pulley to the ceiling and a second chain connects the lower pulley to the crate. Assume the masses of the chains, pulleys, and ropes are negligible.

Determine the force required to lift the crate with constant speed.

Determine the tension in the upper chain, and lower chain.

C ( )
| O |
| | \
| | \
| | (Force via hand)
O )
|
[52kg]

Sorry for such a crude drawing but if you imagine the lines as the rope, the parentheses as curves in the line, and O's as the pulleys. C = Cieling

My thoughts were that tension must be halved in one sense or another, but I cant seem to get the math to work out involved, perhaps Im missing the equations entirely.

Actually, the Mechanical advantage is two(two ropes are pulling on the 52kg mass, so you are right. Tension is 52g/2

The tension in the upper, and lower rope is 52g

I am not certain what equations you are working with. At the lower pulley,

Let T up be +
T+T-mg=0

To determine the force required to lift the crate with constant speed in a pulley system, we need to analyze the forces acting on the system.

1. First, let's consider the forces acting on the crate itself:
a) The weight of the crate is equal to its mass multiplied by the acceleration due to gravity (9.8 m/s^2). In this case, the weight of the crate is 52 kg * 9.8 m/s^2 = 509.6 N.
b) The tension in the lower chain is responsible for counteracting the weight of the crate.

2. Next, let's consider the forces acting on the upper chain:
a) The tension in the upper chain is responsible for supporting the weight of the crate.
b) The tension in the upper chain is equal to the force required to lift the crate with constant speed.

Now, let's determine the force required to lift the crate with constant speed:

In an ideal pulley system, the tension in the upper chain is the same throughout the system.

Since the crate is being lifted with constant speed, the tension in the upper chain must equal the weight of the crate. Therefore, the force required to lift the crate with constant speed is 509.6 N.

Now, let's determine the tension in the upper chain and lower chain:

Since the tension in the upper chain is equal to the weight of the crate (509.6 N), the tension in the upper chain is also 509.6 N.

Since the pulley system is ideal and massless, the tension in the lower chain is the same as the tension in the upper chain. Therefore, the tension in the lower chain is 509.6 N as well.