I did not understand the lesson today in my Chemistry I honors class.
We went over the Law of Conservation of Mass for roughly 15 minutes and he gave us this worksheet. Could someone please display how to do this, I'll pull a problem from the worksheet.
When 9.56g of Copper Sulfide (CuS) is heated in the presence of 4.80g of Oxygen (O), the products contain 55.4% Copper Oxide. What is the total mass of products? What mass of copper oxide is formed?
My equations so far looks similar to this:
CuS + O -----> CuO 55.4%
9.56g .36g xg
I'm not exactly sure what the problem does but I think the idea is to show that the only way we can obtain 55.4% CuO is this way.
The mass of the reactants is 9.56 g + 4.08 g = 14.36 g.
The Law of Conservation of Mass says that the products must also have a mass of 14.36 g. So how much CuO would form if we had 55.4% CuO? It would be (x/0.554) = 14.36 or
0.554 x 14.36 = 7.95 g.CuO
The other product is SO2 and the mass of that will be 14.36 x 0.446 = 6.41 g
Very helpful, thank you. I will try this method on other similar problems, and yes, I was not sure what the whole point of the problem is. Thanks once again!
To solve this problem, we need to use the Law of Conservation of Mass, which states that matter cannot be created or destroyed during a chemical reaction, only rearranged.
First, let's calculate the mass of CuO formed. We know that the percentage of CuO in the products is 55.4%. To find the mass of CuO, we can use the formula:
Mass of CuO = Percentage of CuO * Total mass of products
Mass of CuO = 0.554 * Total mass of products (equation 1)
Next, let's determine the total mass of products. We started with 9.56g of CuS and 4.80g of O. These two react to form the products. So the total mass of the products will be the sum of the masses of CuS and O:
Total mass of products = Mass of CuS + Mass of O (equation 2)
We are given that the mass of O is 0.36g. Substituting this value into equation 2, we get:
Total mass of products = 9.56g + 0.36g
Now we can substitute this value into equation 1 to find the mass of CuO:
Mass of CuO = 0.554 * (9.56g + 0.36g)
Finally, to find the total mass of products, we substitute the value of the mass of CuO back into equation 2:
Total mass of products = 9.56g + 0.36g + Mass of CuO
Now, let's calculate the values:
Mass of CuO = 0.554 * (9.56g + 0.36g)
Mass of CuO = 0.554 * 9.92g
Mass of CuO ≈ 5.48g
Total mass of products = 9.56g + 0.36g + 5.48g
Total mass of products ≈ 15.4g
Therefore, the total mass of products is approximately 15.4g, and the mass of CuO formed is approximately 5.48g.