Janet left her college campus 2 h after Juanita. They traveled in opposite directions. Janet drove at 50 mi/h and Juanita drove at 62 mi/h. How many hours after Juanita left were the two girls 380 miles apart?
My work:
380 = 50(t-2)+62t
380 = (50t-100)+62t
380 = 112t-100
480 = 112t
/112= /112
4.285714286 = t
-Did I get "t" right?
-And if I didn't what did I do wrong?
Your right!!!
I am?!?! Woo! Thank you!!!
Your calculation for "t" is not correct. Let's go through the solution step by step to identify the mistake.
First, we can set up equations to represent the distance traveled by Janet and Juanita:
Distance traveled by Janet = Janet's speed * time Janet traveled = 50 * (t - 2)
Distance traveled by Juanita = Juanita's speed * time Juanita traveled = 62 * t
Since they traveled in opposite directions, to find the total distance apart, we can add these distances:
Distance apart = Distance traveled by Janet + Distance traveled by Juanita
Now, we can substitute the values into the equation and solve for "t":
380 = 50 * (t - 2) + 62 * t
380 = 50t - 100 + 62t
380 = 112t - 100
To solve for "t," we need to isolate the variable, so let's move the constant term to the other side of the equation:
112t - 100 = 380 + 100
112t = 480
Now, divide both sides of the equation by 112 to solve for "t":
t = 480 / 112
t ≈ 4.2857
So, the correct value for "t" is approximately 4.2857 hours.
Therefore, the two girls were approximately 380 miles apart 4.2857 hours after Juanita left.