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A long-distance runner runs 3 miles south and then 7 miles east. How far is the runner from the starting point

A) 8.616 mi

B) 10 mi

C) 7.616 mi

D) 4.472 mi

I think it is eaither A or C but not sure

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badatmath

  1. Using the Pythagorean Theorem, I found the distance to be 7.616 miles.

    a^2 + b^2 = c^2
    3^2 + 7^2 = c^2
    9 + 49 = 58
    square root of 58 = 7.616

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    Ms. Sue

  2. simple case of using Pythagoras

    d^2 = 3^2 + 7^2
    d^2 = 58
    d = √58 = 7.616

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    Reiny

  4. http://www.arcytech.org/java/pythagoras/history.html

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    bobpursley

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