Tanya is 12 years older than leah. Three years ago, Tanya was five times as old as leah. How old is leah?
let Leah present age be x yrs
then Tanya is now x+12
Three years ago, Leah was x-3
and Tanya was x+12 - 3 or x+9
at that time "Tanya was five times as old as leah"
x+9 = 3(x-3)
x+9 = 3x - 9
18 = 2x
x = 9
So Leah is now 9, and Tanya is now 21
check:
three years ago Leah was 6 and Tanya was 18
Was Tanya three times as old?
is 18 equal to 3 times 6?
Tanya's age t is three times Martin's age m.
To solve this problem, we can start by setting up equations based on the information given.
Let's assume that Leah's age is x. Therefore, Tanya's age is x + 12 since Tanya is 12 years older than Leah.
Three years ago, Leah's age was x - 3, and Tanya's age was (x + 12) - 3.
According to the given information, Tanya was five times as old as Leah three years ago:
(x + 12) - 3 = 5 * (x - 3)
Now, we can solve this equation to find Leah's age.
Expanding the equation:
x + 12 - 3 = 5x - 15
Simplifying:
x + 9 = 5x - 15
Subtracting x from both sides:
9 = 4x - 15
Adding 15 to both sides:
24 = 4x
Dividing both sides by 4:
x = 6
Therefore, Leah is 6 years old.