find the x and y intercept of the function
y=3x+4
y=x^2+7x+12
for the y intecept, set x to zero.
for the x intercept,set y to zero.
can you show me the set up
What must be added to 3x -7 to make x2 + 4x -1?
To find the x-intercept of a function, set y to zero and solve for x.
For the first function, y = 3x + 4, when y = 0:
0 = 3x + 4
Subtract 4 from both sides:
-4 = 3x
Divide both sides by 3:
-4/3 = x
So the x-intercept of the first function is x = -4/3.
To find the y-intercept of a function, set x to zero and solve for y.
For the first function, y = 3x + 4, when x = 0:
y = 3(0) + 4
Simplify:
y = 0 + 4
y = 4
So the y-intercept of the first function is y = 4.
Now let's move on to the second function, y = x^2 + 7x + 12.
To find the x-intercepts:
Set y to zero:
0 = x^2 + 7x + 12
This is a quadratic equation. We can factorize it or use the quadratic formula to find the solutions.
Factoring, we can rewrite it as:
0 = (x + 3)(x + 4)
Setting each factor equal to zero:
x + 3 = 0
x = -3
x + 4 = 0
x = -4
So the x-intercepts of the second function are x = -3 and x = -4.
To find the y-intercept, we set x to zero:
y = (0)^2 + 7(0) + 12
Simplify:
y = 0 + 0 + 12
y = 12
So the y-intercept of the second function is y = 12.