how many moles of potassium carbonate will be produced if 400.0 g of potassium hydrogen carbonate are heated

Write the equation.

Balance it.
Convert 400.0 g KHCO3 to moles.
Convert moles KHCO3 to moles K2CO3 from the equation.

To find the number of moles of potassium carbonate produced, we need to use stoichiometry.

First, we need to write the balanced chemical equation for the reaction.

2KHCO3(s) → K2CO3(s) + H2O(g) + CO2(g)

The coefficient of potassium hydrogen carbonate (KHCO3) is 2, which means that 2 moles of KHCO3 react to produce 1 mole of K2CO3.

Next, we need to calculate the molar mass of KHCO3 and K2CO3.

The molar mass of KHCO3 = (1 × 39.10 g/mol) + (1 × 1.01 g/mol) + (1 × 12.01 g/mol) + (3 × 16.00 g/mol) = 100.12 g/mol

The molar mass of K2CO3 = (2 × 39.10 g/mol) + (1 × 12.01 g/mol) + (3 × 16.00 g/mol) = 138.21 g/mol

Now, we can use the following equation to calculate the number of moles of K2CO3.

Moles of K2CO3 = (mass of KHCO3 * 1 mole of K2CO3) / molar mass of KHCO3

Moles of K2CO3 = (400.0 g * 1 mole) / 100.12 g/mol

Moles of K2CO3 ≈ 3.997 moles

Therefore, approximately 3.997 moles of potassium carbonate (K2CO3) will be produced when 400.0 g of potassium hydrogen carbonate (KHCO3) are heated.