given a jar contains four marbles, each a different color: red, blue, green, and yellow. If you draw two marbles from the jar, one after another, replacing the first before drawing the second, what is the probability of getting no yellow marbles?
I got - 3/4(3/4) = 9/16 = 56.25% is this right?
Correct.
To determine the probability of not drawing a yellow marble, we need to consider the probability of not drawing a yellow marble on the first draw and the probability of not drawing a yellow marble on the second draw.
Since every marble is replaced after each draw, the probability of not drawing a yellow marble on the first draw is 3 out of 4, or 3/4.
Similarly, on the second draw, the probability of not drawing a yellow marble is also 3 out of 4, or 3/4.
To find the overall probability of not drawing a yellow marble, we multiply the probabilities of each individual draw:
P(not yellow on first draw) * P(not yellow on second draw) = (3/4) * (3/4) = 9/16
So, you are correct. The probability of not drawing a yellow marble is indeed 9/16, which is approximately 56.25%. Well done!