Three objects are connected as shown in the figure below. They move along a horizontal, frictionless surface, and are pulled to the right with a force Fext = 2.4 N. With the three mass values given as m1 = 604 g, m2 = 744 g, and m3 = 693 g. Calculate the magnitude of the acceleration of the three objects.

t1 t2 Fext
m1-----m2----m3------>

F= (m1+m2+m3) * a

You know F=2.4N and you know all three masses, so convert mass to kg and solve for a.

a=Fext/sumofMasses

T1=a*m1
T2=a*(m1+m2)

i did it slightly differently but thank you!

To calculate the magnitude of the acceleration of the three objects, we can use Newton's second law of motion which states that the acceleration of an object is equal to the net force acting on it divided by its mass.

1. Find the total mass of the three objects:
Total mass (m_total) = m1 + m2 + m3
= 604 g + 744 g + 693 g
= 2041 g (or 2.041 kg)

2. Calculate the net force acting on the system:
Net force (F_net) = F_ext
= 2.4 N

3. Apply Newton's second law to find the acceleration:
a = F_net / m_total
= 2.4 N / 2.041 kg
≈ 1.176 m/s^2

Therefore, the magnitude of the acceleration of the three objects is approximately 1.176 m/s^2.