A student placed 11.0 of glucose (C6H12O6) in a volumetric flask, added enough water to dissolve the glucose by swirling, then carefully added additional water until the 100.-ml mark on the neck of the flask was reached. The flask was then shaken until the solution was uniform. A 50.0ml- sample of this glucose solution was diluted to 0.500L . How many grams of glucose are in 100.ml of the final solution?

Question

A student placed 11.0  of glucose (C6H12O6) in a volumetric flask, added enough water to dissolve the glucose by swirling, then carefully added additional water until the 100.-ml mark on the neck of the flask was reached. The flask was then shaken until the solution was uniform. A 50.0ml- sample of this glucose solution was diluted to 0.500L . How many grams of glucose are in 100.ml  of the final solution?

mn · Answer

kjkjn

e · Answer

grrrr+ne=?

Explain Bot · Answer

To find out how many grams of glucose are in 100 mL of the final solution, we first need to calculate the concentration of the glucose solution after dilution. Here are the relevant data points: Amount of glucose initially added to the flask = 11.0 g Volume of the flask = 100 mL Volume of the sample taken = 50.0 mL Final volume after dilution = 0.500 L First, let's calculate the concentration of the glucose solution in the flask before dilution. Concentration is typically represented in units of g/L. Concentration before dilution = (mass of solute) / (volume of solution) Concentration before dilution = (11.0 g) / (0.100 L) Concentration before dilution = 110.0 g/L Next, we need to determine the mass of glucose in the 50.0 mL sample of the glucose solution. To calculate this, we can use the concentration of the glucose solution before dilution. Mass of glucose in the sample = (concentration before dilution) * (volume of the sample) Mass of glucose in the sample = (110.0 g/L) * (0.050 L) Mass of glucose in the sample = 5.50 g Finally, we need to calculate the concentration of the glucose solution after dilution, and then find the mass of glucose in 100 mL of the final solution. Concentration after dilution = (mass of solute) / (volume of solution) Concentration after dilution = (5.50 g) / (0.500 L) Concentration after dilution = 11.0 g/L Mass of glucose in 100 mL of the final solution = (concentration after dilution) * (volume of the final solution) Mass of glucose in 100 mL of the final solution = (11.0 g/L) * (0.100 L) Mass of glucose in 100 mL of the final solution = 1.10 g Therefore, there are 1.10 grams of glucose in 100 mL of the final solution.

DrBob222 · Answer

11.0 g/100 mL = ?? g/mL. You took 50.0 mL of this solution and diluted to 500 mL. So the final concn is 0.11 g/mL x (50 mL/500 mL) = ?? g/mL. g glucose in 100 mL = ?? g/mL x 100 mL = xx g/100 mL.