I'm trying to solve this Pythagorean Theorom problem.
x^2+(2x^2)=32^2
which becomes
5x^2=1024
I don't get how the x^2 and the 2x^2 combine to get 5x^2. I think it should be 3x^2. Can you explain? Thanks!
The way it is written, is should be 3x^2
are you certain the second term is not (2x)^2 ?
You're right, it is 2x^2.
To solve the equation x^2 + (2x^2) = 32^2, we can first simplify it by combining like terms.
The left side of the equation has two terms: x^2 and 2x^2. These two terms have a common variable, x^2, so we can combine them by adding their coefficients.
The coefficient in front of x^2 is 1, and the coefficient in front of 2x^2 is 2. When we add these coefficients together, we get 1 + 2 = 3.
Therefore, the simplified equation becomes 3x^2 = 32^2.
It seems like you made a small mistake in combining the coefficients. The correct answer is indeed 3x^2, not 5x^2.