use the quadratic formula
2d^2+4=5d
Rearrange in the form
2d^2 - 5d +4 = 0
and apply the quadratic formula. Post your work if you get stuck OR tell us exactly what you don't understand about taking the next step.
is the answer:no real roots
because when i used the quadratic formula the square root part in 5+-square root of -7 over 4
right
To solve the quadratic equation 2d^2 + 4 = 5d using the quadratic formula, follow these steps:
Step 1: Rewrite the equation in standard form:
2d^2 - 5d + 4 = 0
Step 2: Identify the coefficients of the quadratic equation:
a = 2, b = -5, c = 4
Step 3: Plug the coefficients into the quadratic formula, which is:
d = (-b ± √(b^2 - 4ac)) / (2a)
Step 4: Solve the equation by substituting the coefficients into the quadratic formula:
d = (-(-5) ± √((-5)^2 - 4(2)(4))) / (2(2))
d = (5 ± √(25 - 32)) / 4
d = (5 ± √(-7)) / 4
Since the radical term is negative (√(-7)), the equation has no real solutions. In other words, there are no values of d that satisfy the equation. Hence, the quadratic equation 2d^2 + 4 = 5d has no solution.