In outer space, a constat net force of magnitude 140 N is exerted on a 32.5 kg probe initially at rest. (a) what acceleration does thie force produce? (b) how far does the probe travel in 10.0 s?
see other post.
To find the answers, we can use Newton's second law of motion, which states that the net force acting on an object is equal to the product of its mass and acceleration (F = m * a).
(a) To find the acceleration produced by the force, we can rearrange the equation to solve for acceleration:
a = F / m
Given that the force (F) is 140 N and the mass (m) of the probe is 32.5 kg, we can substitute those values into the equation:
a = 140 N / 32.5 kg = 4.31 m/s²
Therefore, the acceleration produced by the force is 4.31 m/s².
(b) To find the distance traveled by the probe in 10.0 seconds, we can use the equations of motion. The equation we will use is:
d = v₀t + (1/2)at²
Where:
d = distance traveled
v₀ = initial velocity (since the probe is initially at rest, the initial velocity is 0)
t = time taken
a = acceleration
Substituting the values into the equation:
d = 0 * 10.0 s + (1/2) * 4.31 m/s² * (10.0 s)²
Simplifying:
d = 0 + (1/2) * 4.31 m/s² * 100 s²
d = 2.155 m/s² * 100 s²
d = 215.5 m
Therefore, the probe travels a distance of 215.5 meters in 10.0 seconds.
a= F/mass
=135/31.2
=4.2857
d= 1/2a t^2= 1/2 F/m t^2
=1/2(4.2857)(15)^2
=1/2(4.2857)(225)
=482.14
=482