use quadratic formula y^2+9=-9y
o and when i solve it all, the answer seems wrong
I get -1.15 and -7.85 to three sig figures.
21-7x/14
To solve the equation y^2 + 9 = -9y using the quadratic formula, we need to rearrange the equation into standard quadratic form, which is ax^2 + bx + c = 0.
First, let's rewrite the equation by moving all the terms to one side:
y^2 + 9 + 9y = 0
Now, we can apply the quadratic formula:
The quadratic formula is given by x = (-b ± √(b^2 - 4ac))/(2a), where a, b, and c are the coefficients of the quadratic equation.
For our equation y^2 + 9 + 9y = 0, we have:
a = 1 (coefficient of y^2),
b = 9 (coefficient of y),
c = 9 (constant term)
Substituting the values into the quadratic formula, we get:
y = (-9 ± √(9^2 - 4 * 1 * 9))/(2 * 1)
Simplifying further:
y = (-9 ± √(81 - 36))/(2)
y = (-9 ± √45)/(2)
Now, let's find the two possible solutions:
1. y = (-9 + √45)/2
2. y = (-9 - √45)/2
These are the solutions to the quadratic equation y^2 + 9 = -9y using the quadratic formula.